Kepler Orbit

  • #1
127
0
Sorry if this is in the wrong forum.

I have the equation [tex]r = \frac{a(1-e^2)}{1+e \cos \theta} [/tex],
and I'm wondering what the physical significance of the numerator is.
More specifically, what is 'a' (since e is what it usually is)?

I've seen various other representations with terms like angular momentum on the top (or rather h^2/GM).

In the context of what I'm doing, it's written this way to (presumably) uncover any implicity 'e'-dependence in the orbit.
 

Answers and Replies

  • #2
Janus
Staff Emeritus
Science Advisor
Insights Author
Gold Member
3,651
1,551
'a' is the semi-major axis of the orbit, or the average value of 'r' for the orbit.
 

Related Threads on Kepler Orbit

  • Last Post
Replies
4
Views
3K
  • Last Post
Replies
4
Views
1K
  • Last Post
Replies
2
Views
921
  • Last Post
2
Replies
28
Views
20K
  • Last Post
Replies
8
Views
7K
Replies
10
Views
4K
Replies
5
Views
3K
Replies
2
Views
2K
Replies
1
Views
1K
Replies
21
Views
11K
Top