Kepler Orbit

  • #1
Jerbearrrrrr
127
0
Sorry if this is in the wrong forum.

I have the equation [tex]r = \frac{a(1-e^2)}{1+e \cos \theta} [/tex],
and I'm wondering what the physical significance of the numerator is.
More specifically, what is 'a' (since e is what it usually is)?

I've seen various other representations with terms like angular momentum on the top (or rather h^2/GM).

In the context of what I'm doing, it's written this way to (presumably) uncover any implicity 'e'-dependence in the orbit.
 

Answers and Replies

  • #2
Janus
Staff Emeritus
Science Advisor
Insights Author
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'a' is the semi-major axis of the orbit, or the average value of 'r' for the orbit.
 

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