- #1

Suraj M

Gold Member

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## Main Question or Discussion Point

While proving Kepler's 3rd law we get the equation

$$ \frac{ΔA}{Δt} = \frac{2L}{m}$$

we say L and m are constant,so aerial velocity is constant!

But consider a body going around a black hole really quickly, then the mass would not be constant, right?

So is Kepler's 3rd law violated or am i missing something?

$$ \frac{ΔA}{Δt} = \frac{2L}{m}$$

we say L and m are constant,so aerial velocity is constant!

But consider a body going around a black hole really quickly, then the mass would not be constant, right?

So is Kepler's 3rd law violated or am i missing something?