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Kepler's Third Law

  1. Jun 13, 2006 #1
    Using Kepler's Third Law, give the formula for the period TX of planet X whose orbital radius RX is twice that of earth, RE.

    A. TX=(1 Year)x(RX/RE)^3
    B. TX^2=(1 Year)x(RX/RE)^3
    C. TX=(1 Year)x(RE/RX)^3
    D. TX^2=(1 Year)x(RE/RX)^3

    My book is not giving me a formula to use, so i a totally stuck... and ideas?
  2. jcsd
  3. Jun 13, 2006 #2
    What does Kepler's third law say?
  4. Jun 13, 2006 #3
    thats part of the problem, i dont know what it says
  5. Jun 13, 2006 #4


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