Using Kepler's Third Law, give the formula for the period TX of planet X whose orbital radius RX is twice that of earth, RE.(adsbygoogle = window.adsbygoogle || []).push({});

A. TX=(1 Year)x(RX/RE)^3

B. TX^2=(1 Year)x(RX/RE)^3

C. TX=(1 Year)x(RE/RX)^3

D. TX^2=(1 Year)x(RE/RX)^3

My book is not giving me a formula to use, so i a totally stuck... and ideas?

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# Kepler's Third Law

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