Image & Kernel of Linear Transformation: Q1 & Q2

  • Thread starter yukcream
  • Start date
  • Tags
    Images
In summary, the reflection in the line y= x/3 in R-2 sends (5, 8) to (-4, -6). The orthogonal projection onto the plane x+ 2y +3z = 0 in R-3 sends (5, 8) to (0, 0).
  • #1
yukcream
59
0
I just start learning Image and Kernel of Linear Tranfsormation, I find it very confuseing that what is the relationship between span, image and kernel in Transformation T= Ax; x=vector.
Therefore I don't know how to describe the image and kernels of the transformation in :
Q1 : Reflection in the line y= x/3 in R-2
Q2 : Orthogonal projection onto the plane x+ 2y +3z = 0 in R-3

Can anyone help me?
 
Physics news on Phys.org
  • #2
The kernel is the set of vectors mapped to the zero vector. How many vectors are mapped to 0 by any reflection? The image is the set of vectors mapped to. given any vector in R^2 can you see how to find out if it has something mapping to it under the reflection? (it may help to realize that if you do any reflection twice you end up with the identity map).

now try applying the same thinking to the projection. what vectors are mapped to the zero vector? what is the image? obvisouly the image must be a subset of the plane you project into, but which subset?
 
  • #3
matt grime said:
The kernel is the set of vectors mapped to the zero vector. How many vectors are mapped to 0 by any reflection? The image is the set of vectors mapped to. given any vector in R^2 can you see how to find out if it has something mapping to it under the reflection? (it may help to realize that if you do any reflection twice you end up with the identity map).

now try applying the same thinking to the projection. what vectors are mapped to the zero vector? what is the image? obvisouly the image must be a subset of the plane you project into, but which subset?

So So confusing ~~>,< Not quite understand what you mean could you mind elaborate more?
 
  • #4
no, i won't elaborate more. you should try and understand more (maths is not easy, dont' expect to be spoonfed the answer, it will take you some time to understand the definitions. get used to it). as it is the answer follows easily from the definition of kernel. what is the set of vectors mapped to the zero vector?

this undoubtedly sounds harsh (and I'm sure there are people willing to just tell you the answer but that is wrong).


imagine you are doing french. i tell you the endings all regular verbsd take. then i tell you to work out the french for 'i like' given that aimer is a regular verb. would you expect me to spoon feed the answer as j'aime? no, it is up to you to work it out. maths is no different. you have been told that the kernel is the set of vectors sent to 0 so find out what this is.
 
Last edited:
  • #5
Before you work on Q1, I suggest you work on this related problem.

Q0 : Reflection in the line x = 0 (the y-axis) in R-2.

Reflection in this line means that the point whose coordinates are (x, y) will be sent to the point whose coordinates are (-x, y). For instance: (2, 4) will be sent to (-2, 4).

What will (5, 8) be sent to?
What will (-4, -6) be sent to?
What will be sent to (-9, 17)?
What will be sent to (5, -12)?

And now, the $64,000 question:
What will be sent to (0, 0)?

I will get back to you once you have answered these questions.
 
  • #6
matt grime said:
no, i won't elaborate more. you should try and understand more (maths is not easy, dont' expect to be spoonfed the answer, it will take you some time to understand the definitions. get used to it). as it is the answer follows easily from the definition of kernel. what is the set of vectors mapped to the zero vector?

this undoubtedly sounds harsh (and I'm sure there are people willing to just tell you the answer but that is wrong).


imagine you are doing french. i tell you the endings all regular verbsd take. then i tell you to work out the french for 'i like' given that aimer is a regular verb. would you expect me to spoon feed the answer as j'aime? no, it is up to you to work it out. maths is no different. you have been told that the kernel is the set of vectors sent to 0 so find out what this is.

Thanks for your remind on how to learning maths.
what you are talking is just theory, and denfinion all of it I have already got from a book no need to copy it once again for me. I wnat to understand the "application" just, can you tell me the answer. of the question:
Q1 : Reflection in the line y= x/3 in R-2
Q2 : Orthogonal projection onto the plane x+ 2y +3z = 0 in R-3
 
  • #7
go step by step and do what grims said...
ther kernal-->solve the reflections that map O

all else www.mathworld.com, your textbook should ahve examples...if not get a new textbook
 
  • #8
no, i just telling you the answer isn't gonig to help you. draw a picture if it helps you to visualize what is going on in a refelction, any reflection, in a line through the origin. (heck, you can just write out the matrix of the linear map and find its determinant to see that it is an invertible map, whcih incidentally has just told you what the kernel and image are).
learning maths is practical, reading a statement doesn't do anything as you have found out. what have you done in order to try and see what is going on? have you drawn the plane and drawn in the line of reflection? have you thought about how it transforms vectors? What does the map send a point (x,y) or (x,y,z) in the second case to? so when does it send x,y,z to zero? you don't need to work out any equations, you can do it from looking at the picture and thinking geometrically.

or is the problem that you don't know what the maps really do? i project R^3 onto a plane orthogonally, you undertstand that any point in R^3 is of the form w+kn where w is in the plane and n is a unit normal vector orthoginal to the plane, k a scalar. so what does porjection into the plane do to w+kn?
 

1. What is the image of a linear transformation?

The image of a linear transformation is the set of all possible outputs that can be obtained by applying the transformation to every vector in its domain. It represents the range of the transformation and is a subset of the codomain.

2. How is the image related to the kernel of a linear transformation?

The image and kernel of a linear transformation are complementary subspaces. This means that the dimensions of the image and kernel add up to the dimension of the domain. Additionally, the kernel is the set of all input vectors that map to the zero vector in the image.

3. Can the image and kernel of a linear transformation be equal?

Yes, it is possible for the image and kernel of a linear transformation to be equal. This happens when the only vector that maps to the zero vector in the image is the zero vector itself. In this case, the dimension of the domain is equal to the dimension of the image and kernel.

4. How can the image and kernel of a linear transformation be determined?

The image of a linear transformation can be determined by applying the transformation to every vector in its domain and collecting the resulting outputs. The kernel can be determined by solving the equation T(x) = 0, where T is the linear transformation and x is a vector in the domain.

5. Why are the image and kernel important in linear algebra?

The image and kernel of a linear transformation provide important insights into the properties of the transformation. They can help determine if the transformation is one-to-one, onto, or both. They also play a crucial role in solving systems of linear equations and understanding the geometric properties of linear transformations.

Similar threads

  • Linear and Abstract Algebra
Replies
10
Views
2K
Replies
3
Views
1K
  • Linear and Abstract Algebra
Replies
2
Views
975
  • Linear and Abstract Algebra
Replies
4
Views
4K
  • Linear and Abstract Algebra
Replies
1
Views
1K
Replies
2
Views
780
  • Linear and Abstract Algebra
Replies
2
Views
971
Replies
1
Views
2K
  • Calculus and Beyond Homework Help
Replies
9
Views
13K
  • Linear and Abstract Algebra
Replies
2
Views
3K
Back
Top