# Kg force of emf induced

Hi,

I wonder if someone can help me. Looking at magnetic generators, we spin the magnets around which will induce an EMF. This EMF will create a magnetic field opposite that of the magnets, thereby creating a drag. If I had to generate 1 watt for 1 second, how much kg force will I need to spin the magnets forward for that second?

Related Classical Physics News on Phys.org
It depends on the design of the generator, of course, how many windings you have, how many turns each, etc.

Assuming 100% efficiency, power in = power out, and Power=torque X speed...so, depending how fast you want to spin the generator, the torque needed may vary to achieve the 1W output that you want.

In any case, you may benefit from reading http://en.wikipedia.org/wiki/Torque" [Broken].

Last edited by a moderator:
I'm fairly new to all of of this, been a good few years since I was in school, so most of this I have already forgotten. I am waiting for another post to be answered, which will help me to determine most of the detail above, I will be back once I know more.