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How many kilograms of air are contained in a box 2.0m by 5.0m by 10.0m(at 1.0atm and 77 deg F)? Assume the molecular weight of air to be 28g.

This is what I've done so far, and can't come up with the correct answer.

77 deg F = 298 K

V=100m^3=100000 L

PV=nRT

(100000 L)/(298K * .0821 L*atm/mol*K) = 4087 moles

4087 moles / (28g/mole) = 146g or .146Kg air

What did I do wrong??

Thanks for the help fellas!

Brad

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# Homework Help: Kg of air in room

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