- #1

kk727

- 54

- 0

**Question:**1. A football is kicked towards a field goal 28m away. The initial velocity of the ball is 37 m/s. The ball crosses safely through the uprights, while it is 3m above the ground.

a. Find time when it passes through the uprights.

b. Find its max height.

c. Find its launch angle.

## Homework Equations

v = v

_{o}+ at

x = x

_{o}+ v

_{o}t + 1/2at

^{2}

## The Attempt at a Solution

So, we started this problem in class today, and didn't have enough time to solve it completely.

We first split the velocity into its X and Y components:

V

_{o}Y= 37sinθ

V

_{o}X=37cosθ

Using V=x/t, we figured out that 37cosθ=28/t, and t=28/37cosθ.

Then using this equation, we plugged in everything that we had.

3 = 0 + 37sinθt - 4.9t

^{2}

3 = 0 + 37sinθ(28/37cosθ) - 4.9(28/37cosθ)

^{2}

We attempted to solve for t by plugging in 28/37cosθ for it, but ended up getting a bunch of trig, and I personally couldn't solve it. Can anyone help out? Is everything at least right up to here? Thanks in advance!