- #1

Xamfy19

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the hydrogen atom is in ground state when a 15-eV photon interact with it and all the photon's energy is transferred to the electron,, freeing it from the atom.

a) what is the energy of the ejected electron

b) the de Brogle wavelength of the electron.

I thought the energy is 15ev x 1.6 E-19 = 2.4 E-18 J, however, I am not sure the total energy is turned into kinetic energy

I guess if the total energy is kinetic energy, then I can use 1/2 * mv^2 to get v, then

wavelength = h/mv (where h is Planck's constant)

Am I right?

Thanks.