Q: an object is thrown from the ground into the air with a velocity of 20.0m/s at an angle of 27.0 degrees to the horizontal. what is the max height reached by this object? i drew the triangle and found vertical side to be 9.08 m/s and horizontal side to be 17.8m/s using sin and cos. /| 20 / | 9.08 /__| 17.8 but the part i'm having trouble with is how to do the horizontal part of the equation using d=vt. im assuming that i have to use that eqn to find time so i can use that value for the vertical part in finding d, using kinematic formula. in the horizontal part d=vt, what would i use as d? i have v as 17.8 also a side note: for other projectile questions, when would you designate final velocity as unknown, zero, or the negative sign of the initial velocity (ie. initial velocity=14, final velocity = -14) ?