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a

_{y}=2-4t

a

_{x}=-1

v

_{y}=2t-2t

^{2}

v

^{x}=1-t

x

_{0}=2

y

_{0}=3

what is the tangential acceleration when t=1?

what is the radius of curvature of the motion when t=1?

a

_{T}=[tex]\vec{a}[/tex]dot[tex]\vec{v}[/tex]/|v|

at t=1, [tex]\vec{v}[/tex]=0 so there is no tangential acceleration, how can this be true???

the secon part of the question is also not making sence

a

_{r}=v

^{2}/r, but here v=0 and ar=3 since there is no a

_{T}and ax=-1, ay=-2????