1. The problem statement, all variables and given/known data MJ falls from rest from a tall building. 1.5 seconds later SP throws himself downward with an initial velocity of -45 meters per second. Find the distance where they meet. variables: α1= -9.81 α2=-9.81 Δγ1 = ? Δγ2=? Δ†1=? Δ†2=? + 1.5 ∨i1=0 ∨i2=-45 ∨f1=unknown ∨f2=unknown 2. Relevant equations vf=vi+aΔt (distance is absent) Δγ=viΔt+½αΔt^2 (final velocity is absent) 3. The attempt at a solution I think I have the problem right. I found the final velocity and distance where MJ would be after the 1.5 seconds. then I used that final velocity as the initial velocity for MJ. and used that distance as MJ's starting distance. then I used true statements to say the accelerations are the same in both equations, the times are the same in both equations (since I changed my initial velocity and distance) and My distance for spiderman - 11.04 (what I got for the initial distance of MJ) equals MJ's distance. then I used Δγ=viΔt+½Δt^2, and set it up as 11.04=vi1Δt1+½αΔt1^2-vi2Δt2+½αΔt2^2. since I knew my times and accelerations were the same, I knew subtracting ½αΔt2^2 from ½αΔt1^2, leaving me with 11.04=Vi1Δt1- Vi2Δt2. I then subtracted the initial velocities because the times are the same. Then I divided 11.04 by what I got. Would this way give me the correct answer?