This is my first year taking a Physics class, so this might just be a simple question but I'm stuck. 1. The problem statement, all variables and given/known data A stunt driver wants to make his car jump over eight cars parked side by side below a horizontal ramp. (a) With what minimum speed must he drive off the horizontal ramp? The vertical height of the ramp is 1.5m above the cars and the horizontal distance he must clear is 20m. (b) If the ramp is no tilted upward, so that the “take off” angle is 10° above the horizontal, what is the new minimum speed? Note: I already solved part A and got an answer of 35.71m/s 2. Relevant equations Velocity = Initial Velocity + (Acceleration x Time) Distance = Initial Distance + (Initial Velocity xTime) + 1/2(Acceleration)(Time ^2) Velocity ^2 = Initial Velocity ^2 + 2acceleration(Distance - Initial Distance) There might be others too I don't really know, sorry. 3. The attempt at a solution As I said before I already got the answer to part A. Did that by simply finding the time, then solving for velocity. What's throwing me off now is the addition of the 10 degree incline. If someone could maybe show me how to account for that slope of the take off ramp, that would be awesome.