- #1

courtrigrad

- 1,236

- 1

So I know that [itex] v_{0} = 96 [/itex], [itex] v_{x} = 0 [/itex] and [itex] a_{x} = 250 [/itex]. So is it correct to say [itex] v_{x} = v_{x}_{0} + a_{x}t [/itex] to find the time, or [itex] 0 = 96-250t [/itex] and [itex] t = 0.384 sec [/itex]? Then you use [itex] x-x_{0} = v_{x}_{0}t + \frac{1}{2}a_{x}t^{2} [/itex] and you get the distance to be [itex] 18.432 m [/itex]

Is this correct?

Thanks