a basket ball is dropped from a height of 10 m and at a horizontal distance of 2 m from a light pole. A light source at the top of the light pole is 15 m above the ground. How fast is the shadow of the ball moving along the ground one second after the ball is dropped? it can be assumed that t seconds after the ball is released, the distance dropped is given by s = 5t2
kinematics (I suppose)
The Attempt at a Solution
I don't have any ideas..
This is the thing that I've done :
after 1 s :
s = 5 m
v = u + at = 9.8 ms-1
I don't know what to do about the shadow....