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## Homework Statement

a basket ball is dropped from a height of 10 m and at a horizontal distance of 2 m from a light pole. A light source at the top of the light pole is 15 m above the ground. How fast is the shadow of the ball moving along the ground one second after the ball is dropped? it can be assumed that t seconds after the ball is released, the distance dropped is given by s = 5t

^{2}

## Homework Equations

kinematics (I suppose)

## The Attempt at a Solution

I don't have any ideas..

This is the thing that I've done :

after 1 s :

s = 5 m

v = u + at = 9.8 ms

^{-1}

I don't know what to do about the shadow....

Thanks