- #1

- 10

- 0

a = 3 meters squared

v1 = 0?

v2 = ?

Δd = ?

Δt = 10s

Why is velocity 1, 0? Why is delta t 10 seconds?

You are using an out of date browser. It may not display this or other websites correctly.

You should upgrade or use an alternative browser.

You should upgrade or use an alternative browser.

- Thread starter jbeannie05
- Start date

- #1

- 10

- 0

a = 3 meters squared

v1 = 0?

v2 = ?

Δd = ?

Δt = 10s

Why is velocity 1, 0? Why is delta t 10 seconds?

- #2

tiny-tim

Science Advisor

Homework Helper

- 25,836

- 251

hi jbeannie05! welcome to pf!

Why is velocity 1, 0? Why is delta t 10 seconds?

v

∆t is the time from start to finish: since it says it accelerates "for 10s", that means ∆t = 10

now apply the usual constant acceleration equations …

what do you get?

(btw, it's

- #3

- 218

- 1

Δt is also given to you: the car accelerates during 10s

With this you must have seen the formulas to deduce v2 (the velocity after 10s) and the total distance travelled.

- #4

- 48

- 0

Δd=v1Δt+aΔt^2

This should answer your question.

This should answer your question.

- #5

tiny-tim

Science Advisor

Homework Helper

- 25,836

- 251

Δd=v1Δt+aΔt^2

erm … 5 out of 10

- #6

- 48

- 0

- #7

- 10

- 0

a = 3 metres per second-squared

v1 = 0?

v2 = ?

Δd = ?

Δt = 10s

So, a is the acceleration, which is at 3 metres per second-squared, the initial velocity is 0, because the question says it starts "from rest", Δt, this will determine the interval of time used in determining the velocity, I think, not sure, and v2 and Δd is unknown. Am I right so far?

- #8

- 1,065

- 10

Here in the problem you have to find average velocity.

You are given value of acceleration which is assumed to be constant.

From this value you can find average velocity.

- #9

- 15

- 0

you are right on so far

- #10

- 10

- 0

A car accelerates at 3 metres per second-squared from rest for 10s. How far does it travel?

a = 3 metres per second-squared (acceleration)

v1 = 0? (initial velocity)

v2 = ? (final velocity)

Δd = ? (displacement) how far does something travel?

Δt = 10s (interval) time

So, a is the acceleration, which is at 3 metres per second-squared, the initial velocity is 0, because the question says it starts "from rest", Δt, this will determine the interval of time used in determining the velocity. v2 and Δd is unknown.

Am I right so far?

a = 3 metres per second-squared (acceleration)

v1 = 0? (initial velocity)

v2 = ? (final velocity)

Δd = ? (displacement) how far does something travel?

Δt = 10s (interval) time

So, a is the acceleration, which is at 3 metres per second-squared, the initial velocity is 0, because the question says it starts "from rest", Δt, this will determine the interval of time used in determining the velocity. v2 and Δd is unknown.

Am I right so far?

Last edited:

- #11

- 1,065

- 10

I'm not sure what you know about Kinematics, for a start one dimension.

- #12

- 10

- 0

one dimension?

- #13

tiny-tim

Science Advisor

Homework Helper

- 25,836

- 251

(just got up :zzz:)

So, a is the acceleration, which is at 3 metres per second-squared, the initial velocity is 0, because the question says it starts "from rest", Δt, this will determine the interval of time used in determining the velocity. v2 and Δd is unknown.

Am I right so far?

completely!

now look up the standard constant acceleration equations, and apply one of them

- #14

- 10

- 0

a = 3 metres per second-squared (acceleration)

v1 = 0? (initial velocity)

v2 = ? (final velocity)

Δd = ? (displacement) how far does something travel?

Δt = 10s (interval) time

So, a is the acceleration, which is at 3 metres per second-squared, the initial velocity is 0, because the question says it starts "from rest", Δt, this will determine the interval of time used in determining the velocity. v2 and Δd is unknown.

Δd = v1Δt + one half 2 squared

Δd = 0Δt + one half 3 metres per second-squared 10s 2 squared

Is that the right equation to use?

- #15

- 1,065

- 10

a = 3 metres per second-squared (acceleration)

v1 = 0? (initial velocity)

v2 = ? (final velocity)

Δd = ? (displacement) how far does something travel?

Δt = 10s (interval) time

So, a is the acceleration, which is at 3 metres per second-squared, the initial velocity is 0, because the question says it starts "from rest", Δt, this will determine the interval of time used in determining the velocity. v2 and Δd is unknown.

Δd = v1Δt + one half 2 squared

Δd = 0Δt + one half 3 metres per second-squared 10s 2 squared

Is that the right equation to use?

Δd is how far(vector) it is from the origin.

- #16

- 3,816

- 92

Δd = v1Δt + one half 2 squared

Umm..what does this mean? Did you follow the link posted by tiny-tim?

- #17

- 10

- 0

a = 3 metres per second-squared (acceleration)

v1 = 0? (initial velocity)

v2 = ? (final velocity)

Δd = ? is how far(vector) it is from the origin.

Δt = 10s (interval) time

So, a is the acceleration, which is at 3 metres per second-squared, the initial velocity is 0, because the question says it starts "from rest", Δt, this will determine the interval of time used in determining the velocity. v2 and Δd is unknown.

Δd = v1Δt + ½at^2

Δd = (0)(Δt) + ½(3m/s^2)(10s)^2

Is that the right equation to use?

- #18

tiny-tim

Science Advisor

Homework Helper

- 25,836

- 251

(try using the X

Δd = v_{1}Δt + ½at^{2}

Δd = (0)(Δt) + ½(3m/s^{2})(10s)^{2}

Is that the right equation to use?

yup!

- #19

- 10

- 0

Δd = (0)(Δt) + ½(3m/s2)(10s)2

How would I calculate this on a calculator?

How would I calculate this on a calculator?

- #20

tiny-tim

Science Advisor

Homework Helper

- 25,836

- 251

wot? a half times 3 times 10-squared??

i did that *in my head*, and got 149.9999

- #21

- 10

- 0

(0)(Δt) How would I calculate this equation or what does that equation equal?

- #22

TSny

Homework Helper

Gold Member

- 13,159

- 3,458

What do you get when you multiply the number zero times any other number?

- #23

- 10

- 0

- #24

tiny-tim

Science Advisor

Homework Helper

- 25,836

- 251

Is ()() always multiplication?

ah, yes …

if there's nothing between two terms (on the same level), then it's *always* multiplication

(and so (0)(something) is always 0)

- #25

- 10

- 0

what is 0 + ½?

Share: