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Kinematics & Dynamics

  • Thread starter Kandy
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  • #1
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Object A travels at a constant velocity af 2.0 m/s east, and object B travels in the same direction at a constant velocity of 3.0 m/s. If object B starts 1.0 min after object A, how long (time) will it take object B to catch object A?
 

Answers and Replies

  • #2
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Kandy said:
Object A travels at a constant velocity af 2.0 m/s east, and object B travels in the same direction at a constant velocity of 3.0 m/s. If object B starts 1.0 min after object A, how long (time) will it take object B to catch object A?
You're dealing with constant velocity so you know [itex]d = vt[/itex] applies.

Object A

[tex]d_A = 2.0t[/tex]

Object B

[tex]d_B = 3.0(t + 1.0)[/tex]

Because object B is going to catch object A, the distance will be the same. Can you take it from here?
 
  • #3
27
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I don't quite get it, but this is what I tried:

dB = 3.0(t+1.0)
= 3.0t+3.0

dA = dB
2.0t = 3.0t+3.0
-1.0t = 3.0
t=-3.0

but the answer key shows 1.2 x 10^2 s (2.0 min not -3.0 min)
sorry, but i need more help.
 

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