# Kinematics & Dynamics

Object A travels at a constant velocity af 2.0 m/s east, and object B travels in the same direction at a constant velocity of 3.0 m/s. If object B starts 1.0 min after object A, how long (time) will it take object B to catch object A?

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Kandy said:
Object A travels at a constant velocity af 2.0 m/s east, and object B travels in the same direction at a constant velocity of 3.0 m/s. If object B starts 1.0 min after object A, how long (time) will it take object B to catch object A?
You're dealing with constant velocity so you know $d = vt$ applies.

Object A

$$d_A = 2.0t$$

Object B

$$d_B = 3.0(t + 1.0)$$

Because object B is going to catch object A, the distance will be the same. Can you take it from here?

I don't quite get it, but this is what I tried:

dB = 3.0(t+1.0)
= 3.0t+3.0

dA = dB
2.0t = 3.0t+3.0
-1.0t = 3.0
t=-3.0

but the answer key shows 1.2 x 10^2 s (2.0 min not -3.0 min)
sorry, but i need more help.