- #1

- 44

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## Main Question or Discussion Point

When we apply this equation ?

v^2-u^2=kt^2/2m

v^2-u^2=kt^2/2m

- B
- Thread starter LoveBoy
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- #1

- 44

- 1

When we apply this equation ?

v^2-u^2=kt^2/2m

v^2-u^2=kt^2/2m

- #2

Doc Al

Mentor

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Not sure what that equation is supposed to be. It looks like a mash up of these two:When we apply this equation ?

v^2-u^2=kt^2/2m

##x = x_0 + v_0 t + (1/2) a t^2##

##v^2 = v_0^2 + 2 a \Delta x##

- #3

- 44

- 1

Thanks !Not sure what that equation is supposed to be. It looks like a mash up of these two:

##x = x_0 + v_0 t + (1/2) a t^2##

##v^2 = v_0^2 + 2 a \Delta x##

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