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Kinematics - find velocity and acceleration

  1. Sep 21, 2004 #1
    A particle moves along the x axis accoring to the equation x=2.00+3.00t-t^2 where x is in meters and t is in time. At 3.00s what is the velocity and acceleration. For velocity, I would just take the derivative of x=2.00+3.00t-t^2 and sub in 3.00s and for the acceleration I would have to get the second derivative of x=2.00+3.00t-t^2 and sub in 3.00 seconds. Is this correct?
     
  2. jcsd
  3. Sep 21, 2004 #2
    I believe so. Hurray for calculus!:)
     
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