Hi I have a question A baseball player hits a baseball that lands in stands 24 meters above the playing field.The ball land with velocity of 50 meters per second at angle of 35 degree below the horizontal. a.If a player hits the ball 1 meter above the playing field,what was the velocity of the ball upon leaving the bat? b.What was the horizontal distance traveled by ball c.how long was the ball in air I have done like this: let r be angle in degrees t=2usinr/g time=? velocity=50m/s gravity=10 time= 2*50*sin35/10=5.74s velocty of ball at 1m will be: y=vsinrt-0.5gt 1=usin35*5.74-0.5*10*5.74*5.74 u=50.61m/s b.horizontal distance traveled by ball distance/time=velocity then distance/time=ucosr distance=50cos35*5.74 distance=235m c.Time of the ball in air. t=2usinr/g time=? unitial velocity=50m/s gravity=10 time= 2*50*sin35/10=5.74s Any idea about this question?