[SOLVED] Kinematics in 2-dimesions 1. The problem statement, all variables and given/known data A soccer player kicks the ball toward a goal that is 25.0 m in front of him. The ball leaves his foot at a speed of 19.2 m/s and an angle of 65.8 ° above the ground. Find the speed of the ball when the goalie catches it in front of the net. (Note: The answer is not 19.2 m/s.) 2. Relevant equations x=V(0)t+(1/2)gt^2 V^2=V(0)^2+2gy V= sqrt(Vx^2+Vy^2) 3. The attempt at a solution Ok let me define all the variables I've got so far V(0)= 19.2 Vx0= 7.87 x= 25 (12.5 for one half) gx= 0? (not so sure about this one) Vx= ?(at top of apex ) Vy= 0 (at top of apex) gy=-9.8 y= 15.626 Vy0= 17.5 (initial y veolicty) Ok so the first thing I did was find the inital velocity for the x and y componets using sine and cosine, so V0x= 19.2cos65.8= 7.87 V0y=19.2sin65.8= 17.5 I then used my inital y velocity to find out the heigth (y distance) of the shot Vy^2= Vy0^2+2gy 0= (17.5)^2+2(-9.8)y y= 15.625 I'm unsure where to go now in order to out the speed of the ball when the goalie catches it i know that V= sqrt (Vx^2+Vy^2). Should i try and figure out the two final velocities and then plug them into that equation?