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## Homework Statement

Two motorcycles are traveling due east with different velocities.

Four seconds later, they have the same velocity.

During this 4s interval, motorcycle 1 has an average acceleration of 2.0 m/s(squared) due east, while motorcycle 2 has an average acceleration of 4.0 m/s(squared) due east.

By how much did the speeds differ at the beginning of the 4s interval, and which motorcycle was moving faster.

## Homework Equations

No clue

## The Attempt at a Solution

Motorcycle 1 acceleration = 2.0 m/s(squared

So, in 4s, the distance covered is 8 meters.

Motorcycle 2 acceleration = 4.0 m/s(squared)

So, in 4s, the distance covered is 16 meters.

They are both traveling at the same velocity after 4s, so, since motorcycle 2 sped up more to attain the new final velocity, then motorcycle 1 must have been going faster prior to 4s.

Correct?

Now, how do I find the initial velocities of each motorcycle?