Two motorcycles are traveling due east with different velocities.
Four seconds later, they have the same velocity.
During this 4s interval, motorcycle 1 has an average acceleration of 2.0 m/s(squared) due east, while motorcycle 2 has an average acceleration of 4.0 m/s(squared) due east.
By how much did the speeds differ at the beginning of the 4s interval, and which motorcycle was moving faster.
The Attempt at a Solution
Motorcycle 1 acceleration = 2.0 m/s(squared
So, in 4s, the distance covered is 8 meters.
Motorcycle 2 acceleration = 4.0 m/s(squared)
So, in 4s, the distance covered is 16 meters.
They are both traveling at the same velocity after 4s, so, since motorcycle 2 sped up more to attain the new final velocity, then motorcycle 1 must have been going faster prior to 4s.
Now, how do I find the initial velocities of each motorcycle?