1. The problem statement, all variables and given/known data 2. Relevant equations 3. The attempt at a solution First, I find the accelerations of each block, separate the accelerations into Y and X components and then add them as vectors. for B: B goes down the ramp with an acceleration of 3.35 m/s^2 X component : (3.35)(cos 20) = 3.15 m/s^2 to the right Y component : (3.35)(sin 20) = 1.145 m/s^2 downwards for A : I add the Y component of the Normal force of B on A, to the weight of wedge A. Y component of the Normal force of B on A = 80 N Weight of Wedge A = 215.6 N adding both : 80 N + 215.6 N = 295 N but the slope is 30 degrees, so the force along the slope is : (295 N) ( sin 30) = 148 N to find the acceleration of A down the ramp : F = ma 148 N = ( 22 kg) (a) a = 6.72 m/s^2 x component : 5.811 m/s^2 to the left y component : 3.36 m/s^2 downwards now adding components , total x component is 2.66 m/s^2 to the left and 4.505 m/s^2 downwards therefore acceleration of B is 5.23 m/s^2 with direction 59.5 degrees below the the horizontal, directed to the left. Now, all this is wrong because the answer aB =5.94 m/s^2, 75.7 degrees below the horizontal, directed to the right. Where did I go wrong? Did I have the right idea but miscalculated?