# Kinematics of objects on ramp

1. Jul 24, 2016

### goonking

1. The problem statement, all variables and given/known data

2. Relevant equations

3. The attempt at a solution

First, I find the accelerations of each block, separate the accelerations into Y and X components and then add them as vectors.

for B:

B goes down the ramp with an acceleration of 3.35 m/s^2
X component : (3.35)(cos 20) = 3.15 m/s^2 to the right
Y component : (3.35)(sin 20) = 1.145 m/s^2 downwards

for A :
I add the Y component of the Normal force of B on A, to the weight of wedge A.

Y component of the Normal force of B on A = 80 N
Weight of Wedge A = 215.6 N

adding both : 80 N + 215.6 N = 295 N
but the slope is 30 degrees, so the force along the slope is : (295 N) ( sin 30) = 148 N

to find the acceleration of A down the ramp : F = ma

148 N = ( 22 kg) (a)
a = 6.72 m/s^2
x component : 5.811 m/s^2 to the left
y component : 3.36 m/s^2 downwards

now adding components , total x component is 2.66 m/s^2 to the left
and 4.505 m/s^2 downwards

therefore acceleration of B is 5.23 m/s^2 with direction 59.5 degrees below the the horizontal, directed to the left.

Now, all this is wrong because the answer aB =5.94 m/s^2, 75.7 degrees below the horizontal, directed to the right.

Where did I go wrong? Did I have the right idea but miscalculated?

2. Jul 24, 2016

### haruspex

That would be true if the ramp were static. Are you sure it is true if the ramp is itself accelerating?
You need to be clear when discussing B's acceleration whether you mean absolute or relative to A.

3. Jul 24, 2016

### goonking

yes, that was my error, I thought I could take the a point as the origin, and just divide the problem into two separate ones, find the acceleration of both relative to the origin and just add up the vectors but that clearly isn't working out.

I would need to find the acceleration of B relative to A, and in order to do that, I would need to find the acceleration of A (with respect to the origin) first, correct?

4. Jul 24, 2016

### haruspex

You can't do either independently of the other. They are linked by the normal force between them. Introduce that as an unknown and write out the usual F=ma equation for each body.

5. Jul 25, 2016

### yihloong

may i know how do you get this?