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## Homework Statement

A caveman drops a rock from ground-level, into a hole. He counts in seconds until he hears the rock hit the bottom of the hole, and finds that the hole is '16 seconds deep.' Assuming there is no air friction, and the initial velocity of the rock is 0m/s, how deep is the hole? Take into account the speed of sound.

## Homework Equations

h = ½g(T1)²

h = v(T2)

T1 + T2 = 16 sec

## The Attempt at a Solution

Attempt 1:

h = ½g(T1)²

h=½(9.8m/s²)(16s)²

h=4.9m/s²(256s)

h=1254.4m

h=v(T2)

1254.4m=340.29m/s(T2)

1254.4m/340.29m/s=T2

T2=3.6862s

h=v(T2)

1254.4m=v(3.69s)

1254.4m/3.6862s=v

v=340.29m/s

T1+T2=16 sec

16s+3.6862s = 19.6862s?

I am confused because the two values do not add up...and than how do i know which variable actually represents the depth of the hole...

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