Ronson drives a rocket sled from rest 25 m up from a15 degree ramp at an acceleration of 8.0 m/s2. The rocket cuts off at the end of the ramp, which happens to be atthe edge of a 75 m high cliff. He freefalls in his sled until he bounces on a trampoline, which is on a 30.0 m high platform, and gives him an upward acceleration of 108 m/s2 for 0.45 s. Again he freefalls, bouncing this time on the ground, which gives him an upward acceleration of 445 m/s2 for 0.12 s. FInally after a third freefall, he stops bouncing, losing all vertical velocity but none of his horizontal velocity. Now that he's on the ground, he slides horizontally, decelerating at 1.5 m/s2 before coming to a stop. How far is the diagonal distance from the top of the ramp to his final resting place? I know you find the diagonal distance by the Pythagorean theorem. One of the lengths of the sides is 75 m while you find the other by adding up the x distances of the jumps. I just don't know what numbers to use for velocity or acceleration in the beginning. Can someone please explain to me how to do this problem? THis is really advanced, and I am really bad at projectiles motion. I know it involves x and y components. It involves kinematic equations V = Vo + at X - Xo = Vot + .5at2 v2 = vo2 + 2a(X - Xo) X - Xo = .5(Vo + V)t If you can provide ideason how for me to solve this, that would be appreciated!