time = 1 seconds, 2 seconds, 3 seconds, 4 seconds, 5 seconds
acceleration due to gravity = -9.8 m/s^2
Max. Height = 3 meters
d = vit + 1/2at^2
v = d/t
The Attempt at a Solution
I actually have to create values myself, so that the as the time increases the height decreases.
This is a scenario where a golf ball on a ramp from the top of the ramp is released, and for each of those time values I mentioned above I need the height.
v = 3m/1s = 3 m/s
d = (3m/s)(1s) + (1/2)(-9.8m/s^2)(1s)^2 = -1.9 m
If I keep increasing the time values my height is going to increase. That is not what i want. Please help.