Kinematics Problem on a bullet

In summary, a rifle with an initial bullet speed of 500 m/s is aimed horizontally at the centre of a large target 200m away. To hit the centre of the target, the barrel must be at an angle above the line of sight. The angle of elevation of the barrel can be calculated by using formulas relating horizontal and vertical distance to time, initial speed, and acceleration due to gravity.
  • #1
frozen7
163
0
A rifle is aimed horizontally at the centre of a large target 200m away. The initial speed of the bullet is 500 m/s.
(a) Where does the bullet strike the target?
(b) To hit the centre of the target, the barrel must be at an angle above the line of sight. Find the angle of elevation of the barrel.

What does (a) mean actually? And can anyone draw out the diagram ? Thanks.
:smile:
 
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  • #2
Part a. is asking for how far below the centre of the target the bullet hits I think. It's a projectile motion problem.
 
  • #3
The how to calculate the value? since we just know how far is the target beyond the rifle.
 
  • #4
(a) If the bullet is aimed directly at the centre of the target and bullet is let out , it will eventually start falling with gravity and will hit a point below the target.Simple projectile motion problem.

BJ
 
  • #5
frozen7 said:
The how to calculate the value? since we just know how far is the target beyond the rifle.

You can work out the time it takes to travel that distance horizontally, then find the vertical distance traveled in the same time.
 
  • #6
does it mean displacement in y-compenent is the value this question ask for?
 
  • #7
Yes.

BJ
 
  • #8
And how to solve the (b) question?
 
  • #9
So that you don't miss the target , you need to raise your gun up making some angle with horizontal.Calculate that angle.

BJ
 
  • #10
The point is that, in order to do this problem, you should have formulas relating the horizontal and vertical distance to time, initial speed, acceleration due to gravity. What formulas do you have to use?
 

1. How do you calculate the initial velocity of a bullet?

The initial velocity of a bullet can be calculated using the equation v = d/t, where v is the velocity, d is the distance the bullet traveled, and t is the time it took to travel that distance. This information can be obtained through measurements or by using data from a ballistic test.

2. What is the equation for determining the maximum height of a bullet?

The equation for determining the maximum height of a bullet is h = v^2sin^2θ/2g, where h is the maximum height, v is the velocity, θ is the angle of elevation, and g is the acceleration due to gravity. This equation assumes no air resistance and a level surface.

3. How does air resistance affect the trajectory of a bullet?

Air resistance, also known as drag, can significantly affect the trajectory of a bullet. As the bullet travels through the air, it experiences a force in the opposite direction of its motion, slowing it down. This causes a decrease in velocity and a change in the trajectory of the bullet.

4. What factors can affect the range of a bullet?

The range of a bullet can be affected by various factors, such as the initial velocity, angle of elevation, air resistance, and gravity. Other factors that can impact the range include the shape and weight of the bullet, as well as any external forces acting on the bullet, such as wind or friction.

5. How can you calculate the time of flight for a bullet?

The time of flight for a bullet can be calculated using the equation t = 2vsinθ/g, where t is the time of flight, v is the velocity, θ is the angle of elevation, and g is the acceleration due to gravity. This equation assumes no air resistance and a level surface.

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