(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

At the base of a frictionless icy hill that rises at 28.0 degrees above the horizontal, a toboggan has a speed of 12.0m/s toward the hill. How high vertically above the base will it go before stopping?

2. Relevant equations

height = [(v*sin (angle))^2] / (2g)

3. The attempt at a solution

height = [(v*sin (angle))^2] / (2g)

height = [(12m/s*sin(28degrees))^2] / (2(9.8m/s^2))

height = 31.74m^2/s^2 / 19.6m/s^2

height = approx 1.62m

I think I made a mistake with the velocity because this answer is incorrect. Can someone help me please and thank you.

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# Homework Help: Kinematics Problem on toboggan

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