1. The problem statement, all variables and given/known data At the base of a frictionless icy hill that rises at 28.0 degrees above the horizontal, a toboggan has a speed of 12.0m/s toward the hill. How high vertically above the base will it go before stopping? 2. Relevant equations height = [(v*sin (angle))^2] / (2g) 3. The attempt at a solution height = [(v*sin (angle))^2] / (2g) height = [(12m/s*sin(28degrees))^2] / (2(9.8m/s^2)) height = 31.74m^2/s^2 / 19.6m/s^2 height = approx 1.62m I think I made a mistake with the velocity because this answer is incorrect. Can someone help me please and thank you.