(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

There are two ships separated by a distance [tex]\gamma[/tex] along a straight coastline. Ship A starts moving perpendicularly to the coastline , and Ship B moves such that its velocity vector always point along the position of Ship A.

Both ships move at same constant speed. After sufficient time, both the ships will move in a straight line with a constant separation. Find this separation.

2. MY ATTEMPT

First, i assumed the constant speed to be v

and let, after time T, both of them move in a straight line.

and let [tex]\theta[/tex] be the angle that the velocity vector of ship B makes with that of the other. ([tex]\theta[/tex] is variable from [itex]\pi / 2 \ \rightarrow \ 0 [/itex] ) . I feel [itex]tan\theta \ = \ \frac{\gamma}{vt}[/itex]

Then [tex]\gamma \ = \ v \ sin \theta \times T [/tex]

and [tex]x \ = \ T (v-vcos \theta) [/tex]

x= constant separation when ships are in a straight line

The problem is, I am unable to get differential equations which i should. How do i convert the known data into differential form ?

Any help is appreciated

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# Homework Help: Kinematics Problem

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