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Kinematics problem

  1. Feb 14, 2008 #1
    What is the angle if the reach is three (3) times the maximum height.

    I put both of the reach and max height formula together to isolate theta

    [tex]p=\frac{V_{0}^{2}sin(2\theta)}{-g}[/tex] and [tex]h_{max}=\frac{V_{0}^{2}sin^{2}\theta}{-2g}[/tex]

    At the end it gave me this:

    [tex]\frac{3sin\theta}{2}=2cos\theta[/tex]

    Am I getting rusty on my trigonometry? How would you solve this?
     
  2. jcsd
  3. Feb 14, 2008 #2
    your solution was right, all u have to do then is to plug it into your calculator and calculate arctan4/3
     
  4. Feb 14, 2008 #3
    I see it. Thank you very much.
     
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