# Kinematics problem

1. Feb 14, 2008

What is the angle if the reach is three (3) times the maximum height.

I put both of the reach and max height formula together to isolate theta

$$p=\frac{V_{0}^{2}sin(2\theta)}{-g}$$ and $$h_{max}=\frac{V_{0}^{2}sin^{2}\theta}{-2g}$$

At the end it gave me this:

$$\frac{3sin\theta}{2}=2cos\theta$$

Am I getting rusty on my trigonometry? How would you solve this?

2. Feb 14, 2008

### Andy_ToK

your solution was right, all u have to do then is to plug it into your calculator and calculate arctan4/3

3. Feb 14, 2008

I see it. Thank you very much.