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I put both of the reach and max height formula together to isolate theta

[tex]p=\frac{V_{0}^{2}sin(2\theta)}{-g}[/tex] and [tex]h_{max}=\frac{V_{0}^{2}sin^{2}\theta}{-2g}[/tex]

At the end it gave me this:

[tex]\frac{3sin\theta}{2}=2cos\theta[/tex]

Am I getting rusty on my trigonometry? How would you solve this?