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## Homework Statement

Two stones are thrown simultaneously, one straight upward from the base of a cliff and the other straight downward from the top of the cliff. The stones are thrown with the same speed.

The height of the cliff is 4 m and the speed with which the stones are thrown is 7 m/s.

find the distance of the crossing point above the ground.

## Homework Equations

gotta use these using the equations y up = v1t + 1/2at^2, and y down = v1t + 1/2at^2

## The Attempt at a Solution

well so far i went v= x / t and found t = x / v, which was 0.6 s i plugged it in both equations, but i dont know what to do next add the displacements or what ????

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