1. The problem statement, all variables and given/known data Two stones are thrown simultaneously, one straight upward from the base of a cliff and the other straight downward from the top of the cliff. The stones are thrown with the same speed. The height of the cliff is 4 m and the speed with which the stones are thrown is 7 m/s. find the distance of the crossing point above the ground. 2. Relevant equations gotta use these using the equations y up = v1t + 1/2at^2, and y down = v1t + 1/2at^2 3. The attempt at a solution well so far i went v= x / t and found t = x / v, which was 0.6 s i plugged it in both equations, but i dont know what to do next add the displacements or what ????