Good Morning,(adsbygoogle = window.adsbygoogle || []).push({});

Just checking my work, your help would be much appreciated.

A bullet is fired vertically into the air at a speed of 512 m/s.

a) To what maximum height will the bullet does the bullet go?

b) How much time passes before the bullet stops rising?

c) What is the velocity of the bullet after 60 seconds?

My Answers:

a)

Vi = 0, Vf = 512, g = -9.8, find d

Vf^2 = Vi^2 + 2ad

512^2 = 2(-9.8)d

262144 = (-19.6)d

262144/(-19.6) = d

13375 m = d

b)

Vi = 0, Vf = 512, g = -9.8, find t

Vf = Vi + at

512 = 0 + (-9.8)t

512/(-9.8) = t

52.24 Secs = t

c)

Vi = 0, g = -9.8, t = 8, find Vf

Vf = Vi + at

Vf = 9.8 * 8

Vf = 78.4 or 78 m/s^2

Thank You

**Physics Forums | Science Articles, Homework Help, Discussion**

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Homework Help: Kinematics Question

**Physics Forums | Science Articles, Homework Help, Discussion**