Solve Kinematics: Find Vi of Flea Jumping 0.390m

[jnimagine]

A flea jmps to a maximum height of 0.390m. Find vi as it leaves the ground.

I thought of using the equation vf^2 = vi^2 + 2ad
but in this case, if i want to find out vi, I get
-vi^2 = 2ad.
and because of the negative, it doesn't work...

How do you solve this problem??

 

[Clairefucious]

A flea jmps to a maximum height of 0.390m. Find vi as it leaves the ground.

I thought of using the equation vf^2 = vi^2 + 2ad
but in this case, if i want to find out vi, I get
-vi^2 = 2ad.
and because of the negative, it doesn't work...

How do you solve this problem??

Acceleration due to gravity: a = -9.8m/s² note the minus sign!

The reason why this is negative: the flea is jumping up (positive direction), acceleration is acting down (negative direction as it is opposite to the direction of the jump)

This cancels out your problem of negative displacement when you realize you are working with vectors that have different directions.

 

[baba89]

To solve this problem, we can use the equation vf^2 = vi^2 + 2ad, where vf is the final velocity, vi is the initial velocity, a is the acceleration, and d is the displacement. In this case, we know that the final velocity is 0 m/s since the flea reaches its maximum height and then falls back down. We also know that the displacement, d, is 0.390m. Therefore, we can rewrite the equation as 0^2 = vi^2 + 2(9.8m/s^2)(0.390m). This simplifies to 0 = vi^2 + 7.64m/s^2. To solve for vi, we can rearrange the equation to vi^2 = -7.64m/s^2 and then take the square root of both sides. This gives us vi = +/- 2.76m/s. However, since the flea is jumping upwards, we can disregard the negative solution and conclude that the initial velocity of the flea as it leaves the ground is 2.76m/s.