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Introductory Physics Homework Help
Find Angle to Throw Snowball for 20m Distance | Kinematics
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[QUOTE="GuN, post: 4504129, member: 487899"] Thanks for the advice.Here's what I got. v initial (x component)=15.0 m/s v (y component)=0 d (x)=20m a (y)=-9.81 m/s^2 a (x)= 0 m/s^2 d (x)=v initial* t t=d/v initial =20/15 =1.33 secondsv final (x component)= v initial (x) +a(x)t but since a (x)=o, v final (x)= v initial (x) so v final (x)=15.0 m/sI think I remember my teacher saying x and y components both have the same time so: v final (y)= v initial (y) + a (y) t but if v intial (y) is zero v final (y)= a (y) t = (-9.81)(1.33)=-13.08 m/s or 13.08 m/s (down)Then I made it into a right triangle, with the x component being 15.0 m/s and the y component being 13.08 m/s. I did tan inverse of 13.08/15 being being 41 degrees. I'm pretty sure this is wrong, because all of my friends and me are getting completely wrong answers, and the teacher's gone on sick leave (without providing answers to the practice assignment), the substitute has no clue what's she doing and the exam based on the homework is in a couple of days. [/QUOTE]
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Introductory Physics Homework Help
Find Angle to Throw Snowball for 20m Distance | Kinematics
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