Disc (R=5m) is rotating in horizontal plane (period T=10 s). Archer and target are located on the same diameter directly opposite each other (Distance between them equals 10m). Archer shoots. Bullets speed v=300m/s. I have to define angle alpha (approx) at which archer have to aim at target. We can assume that [tex]\omega R << v[/tex].(adsbygoogle = window.adsbygoogle || []).push({});

I want to solve this in 1) inertial and 2) rotating frame.

I did:

[tex]2R=vt[/tex]

[tex]d=\omega R t[/tex] (d is length of arc)

[tex]\alpha =d/2R=\omega R/v=2\pi R/Tv[/tex]

But the answer is [tex]4\pi R/Tv[/tex]

What is wrong?

And i don't know how to make it in rotating frame.

I know that i have to take into account Koriolis and centripetal acceleration.

[tex]\vec{a_{rel}}=2\vec{v}_{rel}\times\vec{\omega}+(\omega)^2\vec{r}[/tex]

Help me please make a step further. Thank you

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# Homework Help: Kinematics question

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