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Kinematics stone problem

  • Thread starter myoplex11
  • Start date
  • #1
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1. Homework Statement
A stone A is dropped from rest down a well, and in 1 s another stone B is dropped from rest. Determine the distance between the stones another second later.
The well is 80ft deep


2. Homework Equations
V=V0+at
X =X0+V0t+.5at^2


3. The Attempt at a Solution
nce apart= distance first-distance2nd
= 1/2 g t^2 - 1/2 g(t-1)^2
so, at t=2
= 1/2 g 4 - 1/2 g 1
this is not giving me the correct anwser. Correct anwser is 48.3ft
 

Answers and Replies

  • #2
tiny-tim
Science Advisor
Homework Helper
25,789
249
dnce apart= distance first-distance2nd
= 1/2 g t^2 - 1/2 g(t-1)^2
so, at t=2
= 1/2 g 4 - 1/2 g 1
this is not giving me the correct anwser. Correct anwser is 48.3ft
Hi!

Looks ok to me. What figure are you using for g? :confused:
 
  • #3
Hootenanny
Staff Emeritus
Science Advisor
Gold Member
9,598
6
Your answer is correct. Don't forget to convert meters to feet.
 

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