Kinematics stone problem

  • Thread starter myoplex11
  • Start date
  • #1
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Homework Statement


A stone A is dropped from rest down a well, and in 1 s another stone B is dropped from rest. Determine the distance between the stones another second later.
The well is 80ft deep


Homework Equations


V=V0+at
X =X0+V0t+.5at^2


The Attempt at a Solution


nce apart= distance first-distance2nd
= 1/2 g t^2 - 1/2 g(t-1)^2
so, at t=2
= 1/2 g 4 - 1/2 g 1
this is not giving me the correct anwser. Correct anwser is 48.3ft
 

Answers and Replies

  • #2
tiny-tim
Science Advisor
Homework Helper
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dnce apart= distance first-distance2nd
= 1/2 g t^2 - 1/2 g(t-1)^2
so, at t=2
= 1/2 g 4 - 1/2 g 1
this is not giving me the correct anwser. Correct anwser is 48.3ft

Hi!

Looks ok to me. What figure are you using for g? :confused:
 
  • #3
Hootenanny
Staff Emeritus
Science Advisor
Gold Member
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7
Your answer is correct. Don't forget to convert meters to feet.
 

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