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Kinematics stone problem

  1. Mar 12, 2008 #1
    1. The problem statement, all variables and given/known data
    A stone A is dropped from rest down a well, and in 1 s another stone B is dropped from rest. Determine the distance between the stones another second later.
    The well is 80ft deep

    2. Relevant equations
    X =X0+V0t+.5at^2

    3. The attempt at a solution
    nce apart= distance first-distance2nd
    = 1/2 g t^2 - 1/2 g(t-1)^2
    so, at t=2
    = 1/2 g 4 - 1/2 g 1
    this is not giving me the correct anwser. Correct anwser is 48.3ft
  2. jcsd
  3. Mar 12, 2008 #2


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    Looks ok to me. What figure are you using for g? :confused:
  4. Mar 12, 2008 #3


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    Staff Emeritus
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    Gold Member

    Your answer is correct. Don't forget to convert meters to feet.
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