(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A stone A is dropped from rest down a well, and in 1 s another stone B is dropped from rest. Determine the distance between the stones another second later.

The well is 80ft deep

2. Relevant equations

V=V0+at

X =X0+V0t+.5at^2

3. The attempt at a solution

nce apart= distance first-distance2nd

= 1/2 g t^2 - 1/2 g(t-1)^2

so, at t=2

= 1/2 g 4 - 1/2 g 1

this is not giving me the correct anwser. Correct anwser is 48.3ft

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# Kinematics stone problem

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