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Kinematics within a simulation
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[QUOTE="Delta2, post: 6058995, member: 189563"] First thing, your equation for ##s_b## is not correct, it should be ##s_b=V_{max}*t-0.5a_b*t^2## because it already has speed V_max when it starts to decelerate. So after that just use the equation you wrote ##s=s_a+s_v+s_b## and also use that ##a=V_{max}/5## ##a_b=V_{max}/1## so the equation will become $$s=0.5\frac{V_{max}}{5}*5^2+V_{max}*(\Delta t-6)+V_{max}*1-0.5*V_{max}*1^2$$ (1) where ##s,\Delta t## are given by the simulation task table if I understood correctly from the description of your simulation and are the total distance and the total time of the task. So just solve equation (1) for V_max, it is just a linear equation . [/QUOTE]
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