Kinetic Energy and Work

  • Thread starter ssm11s
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  • #1
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1. A 2 kg book is at rest on a flat frictionless surface at initial position xi=0. A force F= (2.5-x2) is applied on the book. What is the Kinetic Energy of the block as it passes through x=2 m ?



2. W= Int ( force ) ; K= (1/2)mv2 ; W = K1 - K2



3. So I started out with finding the W by taking the integral of F from x=0 to x=2. Then i put the value of the work in the work-kinetic energy equation. And im stuck here cause i don't know where to use the mass of the book.
 

Answers and Replies

  • #2
rock.freak667
Homework Helper
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Well now, the value of your integral is the kinetic energy.

[tex]Change \ in \ kinetic \ energy = \int_{x_1} ^{x_2} F dx[/tex]


Since it started at rest, the initial ke is 0 and the final one is 1/2mv2

so

[tex]\frac{1}{2}mv^2-0=\int_{x_1} ^{x_2} F dx[/tex]
 

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