# Kinetic Energy & Force

Classical physics

Im studying fumdamental concepts & looking at the relationship between kinetic energy & force. The ewuations seem similar, f=ma & k=mv²/2. Any input on the definiton of these to fundamental concepts & there relationship would be helpful.

ZapperZ
Staff Emeritus
Im studying fumdamental concepts & looking at the relationship between kinetic energy & force. The ewuations seem similar, f=ma & k=mv²/2. Any input on the definiton of these to fundamental concepts & there relationship would be helpful.

I don't think they look similar at all. They are certainly different dimensionally.

If you apply a force F on a mass m, over a distance x, then the amount of work done by that force will be equal to INCREASE in the kinetic energy of the mass. That is a simple illustration of the relationship between "force" and "kinetic energy".

Zz.

Ok, so can i say it is required that a force be exerted on a body on order for it to gain or increase in its kinetic energy?

I don't think they look similar at all. They are certainly different dimensionally.

If you apply a force F on a mass m, over a distance x, then the amount of work done by that force will be equal to INCREASE in the kinetic energy of the mass. That is a simple illustration of the relationship between "force" and "kinetic energy".

Zz.

Left you a line. New to this, so i will excise myself now.

I don't think they look similar at all. They are certainly different dimensionally.

If you apply a force F on a mass m, over a distance x, then the amount of work done by that force will be equal to INCREASE in the kinetic energy of the mass. That is a simple illustration of the relationship between "force" and "kinetic energy".

Zz.

Also, if i may inquire for greater understanding, lets consider the physical phenomena of gases that have undergone combustion.
Is it accurate to say, regarding the kinetic energy of these combusted gases, that in the formula k=mv²/2, that the variable m represents the mass of the gas(es), v² equals the square of the velocity of the gas(es), and the variable k is the total kinetic energy of the combusted gas. k, according to the case presented would be of a spontaneous value right? Meaning a total value for a given point on time?

ZapperZ
Staff Emeritus
Also, if i may inquire for greater understanding, lets consider the physical phenomena of gases that have undergone combustion.
Is it accurate to say, regarding the kinetic energy of these combusted gases, that in the formula k=mv²/2, that the variable m represents the mass of the gas(es), v² equals the square of the velocity of the gas(es), and the variable k is the total kinetic energy of the combusted gas. k, according to the case presented would be of a spontaneous value right? Meaning a total value for a given point on time?

I have no idea how this relates to your original question.

I think you should not use "gases" as your example, because a gas requires the understanding of the statistical nature of the system, something which I think you still do not grasp yet, i.e. have you learned statistical thermodynamics?. Try to use something simpler! What about the example I gave you? Did you understand that?

Zz.

I have no idea how this relates to your original question.

I think you should not use "gases" as your example, because a gas requires the understanding of the statistical nature of the system, something which I think you still do not grasp yet, i.e. have you learned statistical thermodynamics?. Try to use something simpler! What about the example I gave you? Did you understand that?

Zz.

Yes, but you didnt look at my feedback which verified at least a vague understanding. Kinetic energy is that of a body in motion, this body, given proper circumstances, can exert a force on another body, thus transfering some or all of its kinetic energy.

I have no idea how this relates to your original question.

I think you should not use "gases" as your example, because a gas requires the understanding of the statistical nature of the system, something which I think you still do not grasp yet, i.e. have you learned statistical thermodynamics?. Try to use something simpler! What about the example I gave you? Did you understand that?

Zz.

What about marbles on slides/rails? I could test acceleration, kinetic energy, gravitational potential energy & force.

ZapperZ
Staff Emeritus
What about marbles on slides/rails? I could test acceleration, kinetic energy, gravitational potential energy & force.

Only if you have learned about rotational energy.

Is there a reason for turning this into a circus?

Zz.

Only if you have learned about rotational energy.

Is there a reason for turning this into a circus?

Zz.

Sorry Zapper, please bear with a student & not be insulting. It would be better if you could advise me of some productive activities that could aid me in the grasping of these concepts; being that you are so much more enlightened.

sophiecentaur
Gold Member
2020 Award
Sorry Zapper, please bear with a student & not be insulting. It would be better if you could advise me of some productive activities that could aid me in the grasping of these concepts; being that you are so much more enlightened.

I see where ZZ is coming from. If you want to advance in these things you need to get as simple as possible and not keep adding complication. To get a grasp, you should start with the very few basic formulae and then, if you want to verify them experimentally, it's essential to use the simplest possible models. If you don't do it that way you end up on a divergent path getting nowhere.

Google simple dynamics experiments or terms like that, if you want some ideas. You can then choose something to suit you.

I see where ZZ is coming from. If you want to advance in these things you need to get as simple as possible and not keep adding complication. To get a grasp, you should start with the very few basic formulae and then, if you want to verify them experimentally, it's essential to use the simplest possible models. If you don't do it that way you end up on a divergent path getting nowhere.

Google simple dynamics experiments or terms like that, if you want some ideas. You can then choose something to suit you.

Thanks, its 'doin me' from here.

sophiecentaur
Gold Member
2020 Award
Thanks, its 'doin me' from here.

Is that good?

Is that good?

I found a decent textbook to give my studying some discipline. Thanks both of you for the feedback, its been disciplining.