- #1

- 117

- 0

You are using an out of date browser. It may not display this or other websites correctly.

You should upgrade or use an alternative browser.

You should upgrade or use an alternative browser.

- Thread starter teclo
- Start date

- #1

- 117

- 0

- #2

Office_Shredder

Staff Emeritus

Science Advisor

Gold Member

2021 Award

- 4,890

- 854

- #3

- 117

- 0

Office_Shredder said:

two particles constrained to each other, free to rotate. each one is described by the position vector a(rhat) + b(theta hat). my velocity would have two components, r and theta. the velocity for each one would be in terms of r and theta, which would (i would think) would cover translational and rotational movement. the last sentence sums up my question fairly well. thanks for your input!-

- #4

- 47

- 0

- #5

- 3,768

- 10

teclo said:if i have a system that i'm describing using polar coordinates, do i need to have an additional term for rotational kinetic energy?

YES

marlon

- #6

- 117

- 0

marlon said:YES

marlon

could you elaborate, please?

- #7

- 6,153

- 1,475

- #8

- 47

- 0

robphy said:

yes, this is definitely the best way to see what is going on if you are confused. Start with just a 1/2mv^2 term for each direction and then sub in the substitutions into polar coordinates, yuo should much of it will cancel out and you will be left with a simple expression with a kinetic energy term for each of your coordinates, r and theta.

- #9

- 43

- 0

http://web.me.com/dmwilliams/photo.jpg

Here is the derivation.

Here is the derivation.

Share: