Kinetic Energy of a cart

1. Nov 18, 2007

feedmeister

Hi all,

This really isn't a homework question, but rather a "coursework" question. It's pretty simple, I'm just trying to understand the concept. It's a workbook problem from my book.

1. The problem statement, all variables and given/known data
A 0.2 kg plastic card and a 20 kg lead cart both roll without friction on a horizontal surface. Equal forces are used to push both carts forward a distance of 1m, starting from rest. After traveling 1m, is the kinetic energy of the plastic cart greater than, less than, or equal to the kinetic energy of the lead cart? Explain.

2. Relevant equations
K.E. = (1/2)m*v^2
F = m*a

3. The attempt at a solution

I think it'd be the same because the velocities would make up for the difference in masses since there's the same amount of force.

If you can explain it to me I'd appreciate it. Thanks.

2. Nov 18, 2007

rl.bhat

Work done on a body = Force X displacement = Change in KE.

3. Nov 18, 2007

feedmeister

Ah, yes I forgot that equation. So I guess I was right.

Thanks!