1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Homework Help: Kinetic energy of a projectile

  1. Apr 21, 2013 #1
    1. The problem statement, all variables and given/known data
    A 1kg mass is projected from the edge of a 20m tall building with a velocity of 20 m/s at some unknown angle above the horizontal. What is the kinetic energy (in J) of the mass just before it strikes the floor?

    2. Relevant equations
    K= [itex]1/2[/itex] m v[itex]^{2}[/itex]

    3. The attempt at a solution
    I couldn't figure out how to get the angle in order to find the kinetic energy.
  2. jcsd
  3. Apr 21, 2013 #2
    You don't need to use the angle in this problem.
    Hint : something is conserved
  4. Apr 21, 2013 #3
    Oh now I got it..

    Ki= 0.5 m vi^2
    Kf= 0.5 m vf^2
    Ui= m g h
    Uf= 0
    ΔK + ΔF = 0
    which will end up
    (v^2 - vo^2) + (-mgh) = 0
    (v^2 - 400) + (-200) = 0
    v^2= 200+400 = 600 m/s

    Kf= 0.5 m v^2
    Kf= 0.5 (1) (600) = 300 J

    Is my solution right?
  5. Apr 21, 2013 #4
    This is the right idea, but there's a mistake in the calculation.
    You can make this simpler by not working out vf first - you don't need it.

    Kf = Ui + Ki
    (where Uf is taken as zero)
  6. Apr 21, 2013 #5
    Well the final answer will be 400 J

    Can I know why this is the proper way? Is it a special case for projectiles or something?
    or the way I used is wrong in general?
    Last edited: Apr 21, 2013
  7. Apr 21, 2013 #6
    If you had the initial angle of the velocity, you could have used the standard kinematic equations to solve the problem.
    Since this wasn't given, and they asked for the final KE suggests that you should use the energy approach.

    Your approach was not wrong - you just did more work by calculating the final speed.

    In this part, you've missed out the 1/2 * m part for the KE :
    if you make this correction, you should get the same answer.
  8. Apr 21, 2013 #7
    I got it now, I really appreciate your help.. thanks :)
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook

Have something to add?
Draft saved Draft deleted