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A 66.0 kg diver is 4.90 m above the water, falling at speed of 8.20 m/s. Calculate her kinetic energy as she hits the water. (Neglect air friction)

Then the problem hints:Use conservation of mechanical energy.

So i'm thinking that conservation is K_f+U_f=K_i+U_i but there must something wrong with my calculations>

K=1/2(m*v^2) and U=mgh right?

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# Homework Help: Kinetic Energy of diver

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