1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Kinetic energy of Rotating Body (in 3D)

  1. Dec 24, 2011 #1
    Ok here is what I did:

    [tex]
    T=\int \vec{\tau} \cdot d\vec{\theta } = \int\frac{\mathrm{d} \vec{L}}{\mathrm{d} t}\cdot d\vec{\theta } = \int \vec{L}\cdot d\vec{\omega} = \int I_{ij}\vec{\omega}\cdot d\vec{\omega}[/tex]
    Where I is the inertia matrix.

    when I carry that out, I get:
    T= 0.5*(I11wx2+I22wy2+I33wz2) + 2*(I12wxwy+I13wxwz+I23wzwy)

    but the real answer has no factor of 2 in the second term. What's wrong?
     
  2. jcsd
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Can you offer guidance or do you also need help?
Draft saved Draft deleted



Similar Discussions: Kinetic energy of Rotating Body (in 3D)
Loading...