Particles A (of mass m and charge Q) and B (of mass m and charge 5Q) are released from rest with the distance between them equal to 0.9773 m. If Q = 8 [tex] \mu C [/tex], what is the kinetic energy of particle B at the instant when the particles are 2.9773 m apart? Answer in units of J. I really don't know how to do this problem. I tried to set it up by using conservation of energy. KE_A + KE_B + U_A + U_B = KE_A + KE_B + U_A + U_B qkQ/.9773 + qk5Q/.9773 = KE_A + KE_B + qkQ/2.9773 + qk5Q/2.9773. I really don't think this setup is right, and I have no idea how I would be able to solve for the final kinetic energy of B when I don't know the final velocity of A. Suggestions?