A crate of mass 10.00kg is pulled up a rough incline with a n initial speed of 1.50m/s. The pulling force is 100N parallel to the incline, which makes an angle of 20.0 degrees with the horizontal. The coefficient kinetic friction is 0.400, and the crate is pulled 5.00m.
What is the change in kinetic energy if the crate?
The Attempt at a Solution
This what i have done but i cannot seem to get the right answer:
To find velocity:
W = 0.5mv^2 + Frictional force * d
500 = 5v^2 + 184
To Find change in kinetic energy:
K = 0.5mv^2
K = 5 * 7.95^2
K = 316