A 7.0 kg bowling ball falls from a 2.0 m high shelf. Just before hitting the floor, what will be its kinetic energy? (g = 9.8 m/s² and assume air resistance is negligible) a. 14 J b. 19.6 J c. 29.4 J d. 137 J Now I tried using the normal Kinetic Energy KE equation KE = 1/2mv² but when I plug 7.0 in for mass, and (9.8 m/s²)(2.0m) for velocity and square it, my answer is much larger than any of the choices. Like 4,705 so I figure I am doing something wrong.