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Kinetic energy

  1. Apr 16, 2008 #1
    1. The problem statement, all variables and given/known data
    How much work is done by an Olympic triathlete who accelerates herself on her bicycle (combined mass of 105kg) from 5 m/s to 10 m/s?

    2. Relevant equations
    Ek = 1/2mv^2
    W = Fapp(d)

    3. The attempt at a solution
    Ek = 1/2m[(5 + 10)/2]^2

    how do i go about solving this?
  2. jcsd
  3. Apr 16, 2008 #2


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    Science Advisor

    Work is the change in energy of an object. So how much did she start with, and how much did she end up with.
  4. Apr 16, 2008 #3
    Is the answer 3937.5 joules?
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