Q26: Electron Gun Physics - Kinetic Energy, Force, Acceleration & Time of Flight

In summary, the problem involves an electron gun in a black-and-white television set that accelerates electrons from rest to 9.60% of the speed of light over a distance of 2.80 cm. The kinetic energy of the electron leaving the gun is 3.7*10^-16 Joules. The constant force acting on the electron is 1.34*10^14 Newtons, the acceleration is 1.48*10^16 m/s^2, and the time of flight is 1.94*10^6 seconds. These values can be calculated using the equation of motion and the mass of the electron.
  • #1
Faiza
96
0
Q26. In the neck of the picture tube of a certain black-and-white television set, an electron gun contains two charged metallic plates 2.80 cm apart. An electric force accelerates each electron in the beam from rest to 9.60% of the speed of light over this distance. (a) Determine the kinetic energy of the electron as it leaves the electron gun. Electrons carry this energy to a phosphorescent material on the inner surface of the television screen, making it glow. For an electron passing between the plates in the electron gun, determine (b) the magnitude of the constant force acting on the electron, (c) the acceleration, and (d) the time of flight.
 
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  • #2
i need help i dun know what to do
 
  • #3
im so lost on this supplementry problme and the text is of no help
 
  • #4
can anyone give me some hints how to solve this porblem, because I am thinking the energy of the electron wud be 1/2mv^2
 
  • #5
:'( ......im so lost
 
  • #6
You know the mass of the electron...

Hence, you were right in thinking 1/2 mv2 is the energy of the electron and v = 0.96C where C is the speed of light...

Now you know the final velocity and the initial velocity of the electron and the distance it travels... come in Newton... equation of motion...

V2 - U2 = 2*Acc*Distance

Which will give you Acc...
Force = Mass * Acc... so there you go...

Proceed along those lines and you should be good...
 
  • #7
its 9.60%=9.60/100=0.096c?? right I am sure that was juss a typo??
 
  • #8
im going to try it
 
  • #9
(a) 3.7*10^-16 Joules
(b)F=1.34*10^.14 Newtons
(c)a=1.48*10^16 m/s^2
(d) time of flight=1.94*10^6 seconds
please check my answers if u have time please
 

1. What is an electron gun and how does it work?

An electron gun is a device that produces a beam of electrons for various applications, such as in cathode ray tubes, electron microscopes, and particle accelerators. It works by using an electric field to accelerate electrons from a cathode (negative electrode) towards an anode (positive electrode), creating a focused and directed beam of electrons.

2. How is the kinetic energy of electrons determined in an electron gun?

The kinetic energy of electrons in an electron gun is determined by the potential difference between the cathode and anode, as well as the distance between them. The higher the potential difference and the shorter the distance, the greater the kinetic energy of the electrons will be.

3. What is the relationship between force and acceleration in an electron gun?

The force acting on an electron in an electron gun is directly proportional to its acceleration. This is described by Newton's second law of motion, which states that the force (F) exerted on an object is equal to its mass (m) multiplied by its acceleration (a): F = m x a.

4. How does the time of flight of electrons in an electron gun affect the beam's accuracy and precision?

The time of flight of electrons in an electron gun is crucial for the accuracy and precision of the beam. If the electrons have a longer time of flight, they may experience more deflection due to external forces, resulting in a less accurate and precise beam. Therefore, minimizing the time of flight is important for maintaining the beam's accuracy and precision.

5. What factors can affect the performance of an electron gun?

Several factors can affect the performance of an electron gun, including the potential difference between the cathode and anode, the distance between them, the shape and design of the electrodes, and the vacuum level in the gun. Additionally, external factors such as magnetic fields and temperature can also impact the performance of the electron gun.

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