- #1
pkossak
- 52
- 0
I realize this problem is like ridiculously easy, but I just don't understand why you get the answer this way.
A 0.2 kg ball is thrown with an initial velocity of 20 m/s at an angle of 30 degrees with respect to the horizontal. What is the kinetic energy of the ball at the top of it's path?
I don't understand why in order to get the answer, you have to use the horizontal velocity componenent, Vx. Shouldn't you just use the velocity as given, and plug it into .5mv^2? Thanks
A 0.2 kg ball is thrown with an initial velocity of 20 m/s at an angle of 30 degrees with respect to the horizontal. What is the kinetic energy of the ball at the top of it's path?
I don't understand why in order to get the answer, you have to use the horizontal velocity componenent, Vx. Shouldn't you just use the velocity as given, and plug it into .5mv^2? Thanks