Kinetic friction of box down a ramp

  • Thread starter runner1738
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A box slides down a ramp inclined at 41 degrees horizonontal with an acceleration of 1.4 m/s^2. The acceleration of gravity is 9.8 m/s^2. Determine the coefficient of kinetic friction between the box and the ramp.

no ideas need any advice
 

Answers and Replies

  • #2
xanthym
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runner1738 said:
A box slides down a ramp inclined at 41 degrees horizonontal with an acceleration of 1.4 m/s^2. The acceleration of gravity is 9.8 m/s^2. Determine the coefficient of kinetic friction between the box and the ramp.

no ideas need any advice
{Net Force On Box Parallel To Ramp} = {Gravity Parallel Component} - {Friction} =
= m*g*sin(41 deg) - K*m*g*cos(41 deg)
= m*g*{sin(41 deg) - K*cos(41 deg)}
= m*a

a = g*{sin(41 deg) - K*cos(41 deg)}
(1.4) = (9.8){(0.6561) - K*(0.7547)}
K = {(1.4/9.8) - 0.6561}/(-0.7547)
K = (0.6801)


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